-5+36v^2=95

Solution for -5+36v^2=95 equation:

-5+36v^2=95

We move all terms to the left:

-5+36v^2-(95)=0

We add all the numbers together, and all the variables

36v^2-100=0

a = 36; b = 0; c = -100;
Δ = b2-4ac
Δ = 02-4·36·(-100)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*36}=\frac{-120}{72}
=-1+2/3
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*36}=\frac{120}{72}
=1+2/3
$